X^2+2x+1=5

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Solution for X^2+2x+1=5 equation:


Simplifying
X2 + 2x + 1 = 5

Reorder the terms:
1 + X2 + 2x = 5

Solving
1 + X2 + 2x = 5

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + X2 + -1 + 2x = 5 + -1

Reorder the terms:
1 + -1 + X2 + 2x = 5 + -1

Combine like terms: 1 + -1 = 0
0 + X2 + 2x = 5 + -1
X2 + 2x = 5 + -1

Combine like terms: 5 + -1 = 4
X2 + 2x = 4

Add '-2x' to each side of the equation.
X2 + 2x + -2x = 4 + -2x

Combine like terms: 2x + -2x = 0
X2 + 0 = 4 + -2x
X2 = 4 + -2x

Simplifying
X2 = 4 + -2x

Reorder the terms:
-4 + X2 + 2x = 4 + -2x + -4 + 2x

Reorder the terms:
-4 + X2 + 2x = 4 + -4 + -2x + 2x

Combine like terms: 4 + -4 = 0
-4 + X2 + 2x = 0 + -2x + 2x
-4 + X2 + 2x = -2x + 2x

Combine like terms: -2x + 2x = 0
-4 + X2 + 2x = 0

The solution to this equation could not be determined.

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